GIVEN: total length of the banner = 30 ft. perimeter of the banner = 96 ft. total width of the rectangle = ? Let, the perimeter be "p" the length be "L" the width be "w" We know, Perimeter (P) of a rectangle = 2 (L + w) Substituting the values of P, L and w , we get, 96 = 2 (30 + w) 96 / 2 = 30 + w 48 = 30 + w 48 - 30 = w 18 = w
So, the width of the rectangular banner is 18 ft.
The cheerleaders are making a rectangular banner with a length of 30 ft and a total **perimeter **(or the total amount of trim) of 96 ft. By solving the perimeter formula of a rectangle, we find that the possible width of the banner is 18 ft. ;
The possible width of the banner is 18 feet, given the length of 30 feet and a maximum perimeter of 96 feet. The perimeter calculation shows that this width allows for the trim limit to be met. Any width less than 18 feet would also maintain the trim requirement, as long as adjustments are made to the length accordingly.
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