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In Mathematics / High School | 2014-10-25

Is the inequality [tex]15f + 9 > 5(5f + 3)[/tex] solvable? If so, what are the real numbers that satisfy it?

Asked by 8910

Answer (3)

5(5f+3) \\\\ 15f+9>25f+15 \\\\ 15f-25f>15-9 \\\\ -10f>6 \ |:(-2) \\\\ 5f < 3 \\\\ f<\frac{3}{5} \\\\ \boxed{f=(-\infty; \frac{3}{5})}"> 15 f + 9 > 5 ( 5 f + 3 ) 15 f + 9 > 25 f + 15 15 f − 25 f > 15 − 9 − 10 f > 6 ∣ : ( − 2 ) 5 f < 3 f < 5 3 ​ f = ( − ∞ ; 5 3 ​ ) ​

Answered by mariamikayla | 2024-06-10

5(5f+3)\\ 15f+9>25f+15\\ 10f<-6\\ f<-\frac{6}{10}\\ f<-\frac{3}{5}"> 15 f + 9 > 5 ( 5 f + 3 ) 15 f + 9 > 25 f + 15 10 f < − 6 f < − 10 6 ​ f < − 5 3 ​

Answered by konrad509 | 2024-06-10

The inequality 5(5f + 3)"> 15 f + 9 > 5 ( 5 f + 3 ) is solvable. The solutions for f are real numbers less than − 5 3 ​ , expressed as ( − ∞ , − 5 3 ​ ) .
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Answered by mariamikayla | 2024-12-27