So when y=32 it is 4x more than the original y which means they've multiplied it by four. Whatever you do to one you have to do to the other side so you multiply 2 by 4 to get 8 so x=8
The **value **of x in the **variation **is 8 when y = 32
How to determine the value of x in the variation
Since y **varies directly **with x, we can express their **relationship **as:
y = kx
where k is the constant of variation.
We can find k using the given values:
-8 = k(-2)
k = -8 / -2 = 4
Now that we know k, we can find x when y = 32:
32 = 4x
x = 32 / 4 = 8
Hence, when y = 32, x = 8.
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Question
If y=-8 when x=-2,find x when y =32
DIrect variation
When y = 32 , the value of x is found to be 8 based on the established relationship of direct variation. The constant of variation was determined to be 4 .
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