What are the real zeros for the function?

\[ f(x) = x^2 - 3x - 28 \]

Factor the equation: (x-7)(x+4) Solve for X: X-7=0 x+4=0 X=7 x=-4 A zero is when the function crosses the x-axis which is solved by setting the function equal to zero.

Answered by Rafid | 2024-06-10

x 2 − 3 x − 28 = 0 x 2 − 7 x + 4 x − 28 = 0 x ( x − 7 ) + 4 ( x − 7 ) = 0 ( x + 4 ) ( x − 7 ) = 0 x = − 4 ∨ x = 7

Answered by konrad509 | 2024-06-10

The real zeros of the function f ( x ) = x 2 − 3 x − 28 are x = 7 and x = − 4 . We determined these by factoring the quadratic equation and solving for x. This approach led us to the two solutions that make the function equal to zero.
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Answered by Anonymous | 2024-10-29