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In English / High School | 2014-10-23

The width of David's rectangular tent is 5 feet. The length is twice the width. David's rectangular air mattress measures 3 feet by 6 feet. If David puts the air mattress in the tent, how many square feet of floor space will be available for the rest of his things?

Asked by damarion

Answer (3)

Tent: Width = 5 Length = 10 so 5x10 = 50
Air mattress: 3x6 = 18
So 50 - 18 = 32 feet. David will have 32 feet of space in the tent leftover for his other things.

Answered by zacharygrau | 2024-06-10

David's tent measures 50 square feet. His mattress takes up 18 square feet, leaving him with 32 square feet of floor space for his other items. ;

Answered by BenicioDelToro | 2024-06-18

David's rectangular tent has an area of 50 square feet, while his air mattress occupies 18 square feet. This leaves him with 32 square feet of available floor space for other items in the tent. The calculations involve determining the areas of both the tent and the mattress and then subtracting the mattress's area from the tent's area.
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Answered by BenicioDelToro | 2024-09-26