The equation of the line that passes through (2,-7) and is perpendicular to 5x+2y=18 is -2x + 5y = -39. ;
The equation of the line that passes through the point 2-7 and is perpendicular to 5x+2y=18 in standard form is 2x - 5y = -24. ;
The equation of the line that is perpendicular to the given line and passes through the point (2, -7) is 2x - 5y = 39. We found the slope of the perpendicular line using the negative reciprocal of the original slope, then used the point-slope form to derive the equation and converted it to standard form. The final equation in standard form is 2x - 5y = 39.
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